Exercise 2b Simple system with overflow

Note: Create a new network called Exercise 2b and setup the timestep before running the network as described in Exercise 1a.

Create the network and run

Navigate to the left panel and click on Build to open the Nodes list.

Drag and drop to the workspace Map:

A new window will pop-up, click on Submit

Visualize the simulated_flow results

Visualize the simulated_volume results for the storage node

Explanation

This network includes a storage node that simulates a reservoir. The objective of this reservoir is to store water. Initially, it starts with a volume of 200 Mm³, and its volume will increase or decrease based on the balance between intake and outtake.

The output1 node attempts to consume 8 Mm³/day from the reservoir, if available. Meanwhile, the catchment1 node contributes 10 Mm³/day to the reservoir. This means that the reservoir is expected to increase in volume over time, as it will receive more water than it releases.

The results show that the reservoir's volume increases until it reaches its maximum volume on April 22, 2024, indicating that it will need to release the extra volume. The release occurs through the outlet node, as output1 cannot take more than 8 Mm³/day. The amount of water that is released through the outlet is 2 Mm³/day, as this is the difference between the amount provided by catchment1 and the amount consumed by the output1 node.

Since output2 does not have an associated penalty, no water is required through this node. However, in case the reservoir fills up, it can function as a spill node.

Increase the demand

Select output_1 node and change Max Flow to 20 Mm³/day

A new window will pop-up, click on Submit

Explanation

The system conditions changed when the demand from the output 1 node increased from 12 Mm³/day to 20 Mm³/day. This change causes the reservoir to empty more quickly. Previously, the reservoir would be empty by Apr 9, 2024, but with the increased demand, it is now projected to be empty earlier, by January 20, 2024.

Once the reservoir is empty, the output 1 node will only receive 10 Mm³/day, which is the flow provided by the catchment node.

Increase the reservoir priority

Select the storage node and change the allocation penalty to -20

Explanation

As we have changed the allocation penalty for the storage node to be the most negative in the system, it now has the highest priority. This means the system will prioritize allocating water to this node.

The storage node starts filling up from the initial 200 Mm³ as per initial conditions until it reaches its maximum capacity of 365 Mm³. Once this maximum volume is reached, any excess water will be released. This capacity is reached by January 16, 2024.

Output 1 is the next priority node in the system. After the storage node is full, the system will begin allocating the excess water to output 1. This excess water is the 10 Mm³/day supplied by the catchment node.

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